What is the total amp draw when 4 60-watt, 120-volt light bulbs are wired in parallel to a 120-volt AC supply?

To determine the total amp draw when four 60-watt, 120-volt light bulbs are wired in parallel to a 120-volt AC supply, first, the current drawn by each individual bulb must be calculated.

Each 60-watt light bulb operates at 120 volts, and the current can be calculated using Ohm's Law, which states that power (in watts) is equal to voltage (in volts) multiplied by current (in amps). Rearranging this formula gives us:

Current (I) = Power (P) / Voltage (V)

For one bulb:

I = 60 watts / 120 volts = 0.5 amps

Since the bulbs are wired in parallel, the total current drawn from the power supply is the sum of the currents through each bulb. Therefore, for four bulbs:

Total current (I_total) = Current of one bulb x Number of bulbs

I_total = 0.5 amps x 4 = 2 amps

This calculation shows that the total amp draw with four light bulbs in parallel is 2 amps. Thus, the answer is correct: the total amp draw for the system is indeed 2 amps.