If one 22 ohm and one 11 ohm heating element are connected in parallel to a 220 volt source, what is the total current in the main feed?

Prepare for the Refrigeration and Air Conditioning Mechanics (313A) Test. Study with flashcards and multiple choice questions, hints and explanations included. Ace your exam!

To determine the total current in the main feed when the heating elements are connected in parallel, we first need to calculate the equivalent resistance of the parallel circuit.

When resistors are connected in parallel, the formula to calculate the total or equivalent resistance ((R_{total})) is given by:

[

\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2}

]

In this case, the resistances are 22 ohms and 11 ohms. Plugging in the values:

[

\frac{1}{R_{total}} = \frac{1}{22} + \frac{1}{11}

]

Finding a common denominator (which is 22), we rewrite the equation:

[

\frac{1}{R_{total}} = \frac{1}{22} + \frac{2}{22} = \frac{3}{22}

]

Now, taking the reciprocal to find (R_{total}):

[

R_{total} = \frac{22}{3} \approx 7.33 \text{ ohms}

]

Next, to find the total current ((I_{

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