If city water enters a water-cooled condenser at 55°F and leaves at 80°F, what is the heat rejection factor if the factor is 1.36?

To determine the heat rejection factor in this scenario, first, it's important to understand how to calculate the heat rejection from the water-cooled condenser. The heat rejection factor essentially relates to the effectiveness of the condenser in removing heat from the refrigerant.

In this context, city water enters the condenser at a temperature of 55°F and exits at 80°F. To find the temperature rise of the water, you would subtract the inlet temperature from the outlet temperature, resulting in a temperature rise of 25°F. This temperature difference is critical for calculating the heat absorbed by the water as it flows through the condenser.

The heat rejection factor indicates how much heat is being extracted per gallon per minute (gmp) of water flow. The factor value provided in the question, 1.36, would typically imply a specific volume of water that can absorb a certain amount of heat per unit of time. Given the calculated temperature change and the heat rejection factor, one can deduce that a rise of 25°F in the water correlates with a heat rejection factor of 1.36 gmp.

When assessing the options presented, the choice of 1.3 gmp is closest to a direct and relevant calculation based on the temperature change (25°F